RS422 basics understanding

I am understanding the basics of RS422. Now, consider a driver (RS422) connected to a reciever. Now, we have a termination resistor of about 100Ohms or 120Ohms. Now, imagine the driver sends out Voc 2V (the differential voltage). Now, if I understand it correctly line A if more positive than line B, then the reciever outputs a logic 1 and vice versa. So, if Vod is 2V, then assuming line A is 2V and Line B is 0V. Please right me if wrong. In this case there is a 100 Ohm termination resistor. Then shouldnt the current path be from the A line into the termination resistor and back into the driver via the B line.

Is my understanding correct till now.

Now, how does the RS422 receiver work - The symbol of the receiver(and the driver) is that of an amplifier. SO, I am assuming that it takes in the difference and amplifies the difference thereby acting as a difference amplifier. Now, I was wondering, the whole current will be sunk via the line B into the driver (please understand that I am connecting a driver to a receiver). Now, the amplifier(or in basic an op-amp) has infinite impedance which means that no current is sunk into the input terminals of the amplifier or rather receiver.

Is my understanding correct on this topic please.

• It would help if you add a schematic/block diagram so we know what you mean b e "Voc", "Line B", etc. – The Photon Oct 30 '15 at 4:32
• Sorry sir. I just put the images. – Board-Man Oct 30 '15 at 4:45