I'm trying to measure the current consumption of an accelerometer using a 1kOhm shunt at Vdd. I've read that there's a ~30kOhm resistor at SA0, so grounding it causes a much higher current draw.
When I indeed ground SA0, I see 100mV over the shunt. However, when it's connected to Vdd, I see -36mV over the shunt (measured using a UNI-T UT39A multimeter). The device works correctly, but this negative voltage doesn't seem right.
Does anyone know why pulling SA0 high causes a reversed current draw?
I've also tried 100R and 10R.
Here's the schematic. Note that I've picked a random part to represent the sensor. The idea is to indicate that the shunt is on the Vdd line.