I'm not entirely sure if I have done the following equation correct or not, but based on the calculations, my multimeter result seems to be incorrect. I have a very simple circuit, containing a 9V battery, an LED (with 3.2 V forward voltage at 24 mA), and a 270 ohm resistor (as shown below).
My question is, when I do the calculations to determine what the current should be in the circuit, I do (voltage / resistance = I), so I get (I = 5.8V / 270 = 0.0214 Amps). This is 21 mA, approximately. When I insert my meter into the circuit, (inserting the meter between + and the LED, breaking the circuit and properly measuring amperage) I obtain a reading of about 2.1 mA. Did I do the calculation wrong?
I am using a Craftsman 82344 autoranging multimeter. Also, when I insert the multimeter into the circuit, the LED no longer illuminates as it should (at least according to the articles I have studied). Any help would be appreciated, if any more details are needed let me know.