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I have tried to solve this problem for a very long time and keep getting the wrong answer but am absolutely baffled at this point what I have wrong.

schematic

simulate this circuit – Schematic created using CircuitLab

My equations are as follows.

vcvs1 = (I2-I1)(-j300)

Loop1: 9+600-j300)I1+j300I2 = 0

Loop2: 2(I2-I1)(-j300)+(-j300)I2+300I2-300I3+j300I1 = 0

Loop3: -1+300I3 - 300I2 = 0

Then (-1)/I3 = Rth

The answer should be 247angle(-16 degree)

But this does not work out to that at all it's something around 90.

Am I just getting something simple wrong?

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  • \$\begingroup\$ vcvs is dependent on what? \$\endgroup\$
    – Ashik Anuvar
    Commented Dec 2, 2015 at 6:35
  • \$\begingroup\$ If you can clarify on what voltage and by what factor does the VSCS depend on, i can help \$\endgroup\$
    – Ashik Anuvar
    Commented Dec 2, 2015 at 7:02
  • \$\begingroup\$ I think it's dependent on the voltage across C1. But this is only IMO. \$\endgroup\$
    – K. Rmth
    Commented Dec 2, 2015 at 8:14
  • \$\begingroup\$ are you sure about the solution 247 <16` ?? i get the solution as 240 + 120i when i take VCVS as 2 times volatge across Vc ,please clarify the vcvs dependency \$\endgroup\$
    – Ashik Anuvar
    Commented Dec 2, 2015 at 8:49
  • \$\begingroup\$ Isn't it: 600 // -j300 // 300 ? \$\endgroup\$
    – Chu
    Commented Dec 2, 2015 at 9:38

1 Answer 1

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I have solved this. The problem is that I was forgetting to remove all independent sources when adding in the new source. By removing the old independent sources and using only the 1V source I get the correct answer.

Rth: 147.2 angle 16degree

Vth: 3.7 angle -15.9degree

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