I've been working through a few examples of Thevenin Equivalent circuits, and came across this one.
Find the Thevenin Equivalent circuit as seen by a load resistance between points A and B.
Finding the equiv. resistance wasn't too hard (75ohms), but I'm having trouble calculating the equiv. voltage.
I've attempted the questions, but am not sure I got the correct answer. Here's my working.
The total voltage of the circuit is 12V because of two aiding voltage sources being in series. From this, you can use a voltage divider between the two 150ohm resistors, getting a value of 6V. Another voltage divider can be used to find the voltage at node B, that being 2.4V.
Not sure I've done the next thing correctly -
I've assumed that Node A is 3V, and since the Thevenin voltage is the difference between Node A and B, Thevenin Voltage = 3-2.4 = 0.6V. Have I done this question correctly?
Anywho, any help is greatly appreciated.