For a two transistor cascode amplifier, how does one determine the base bias resistor ratios? In the design case of a single transistor common emitter, one can use tricks like Ve = Vcc/10 for, from that assuming Vbe ~=0.7V, Vb = Vcc/10+0.7.
Further assuming the base current through the base bias resistors should generally be 10x more than the required base current for the transistor, one can calculate the two base resistors as Rbb (base resistor at the bottom of the potential divider) = Vb/(Ic*10/Beta), Rbt (base resistor at the top of the potential divider) = (Vcc-Vb)(Ic*10/Beta). The collector resistor value can then be calculated roughly as: Vc = (Vcc+Vcc/10+Vce[sat]))/2, Rc = (Vcc-Vc)/Ic.
What rules of thumb and bias calculations can be used for a two transistor cascode amplifier?