# 35W 6V, what wall wart max current needed

If I have a load of 35W at 6V. (5.8A). How would I calculate the input-side current from a 230v UK mains supply?

• Why don't you just look for a wall wart that can supply 6V at currents up to 5.8 amps and forget about what current will be taken from the AC side? Commented Jan 18, 2016 at 18:05
• One would not choose a power supply based on its at-the-wall power draw, unless perhaps you are narrowing down two choices and you've run out of other comparisons. You choose a supply that can provide at least 5.8A at 6V. Commented Jan 18, 2016 at 18:05
• What are you driving at that level? A DC motor? Most DC supplies are 5V or 12V so you're going to spend a lot if you don't buy something specific to your need. If it's for a motor, you might consider a transformer, DC rectifier, and a switch... Commented Jan 18, 2016 at 21:17

You should not chose the wall wart based on the power it uses on the mains side, but the current it can source on the 6V side.

Generally, if all power converters had an efficiency of 100%, you would put as much power in as you get out, meaning that it would need to draw 35W/230V=0.15A on the mains side. However, since there's no way of telling how efficient an arbitrary power supply is going to be, you will need to grossly oversize this.

By the way, 35W is relatively hefty for a "wall wart" form factor power supply. This definitely sounds more like small laptop power supply.

Please also consider the cabling involved: At 5.8A, assuming a cable length of 1m, the typical AWG 26 cable has a resistance of 0.134 Ohms one way, meaning that 5.8A*2*0.134 Ohms = 1.55V is wasted on heating the copper cable, meaning that less than 4.5V are actually available to your device, if that happens to draw a constant current, but more likely, it will see a inner source resistance of 0.268 Ohms, meaning that voltage at the device will fluctuate with the power it draws. Under no circumstances you'd want that.

Hence: Oversize a bit. Get a power supply that offers at least 6.5A. In fact, on uk.farnell.com I couldn't find a single plug-in supply AC/DC supply for 6V that offers at least 6.66A that was in Stock in Europe. 6V with that much current just isn't very common.

• I don't know who "typically" uses 26 AWG for power supply wire, but it's not me unless it's a very light draw (and my default then is 24 anyway...) - also it does no good whatsoever to "oversize the amps" if you are connecting to undersized wire, since the the voltage will still be too low due to wire resistance and current flow. Commented Jan 18, 2016 at 19:50

6V power supplies at the Amps you need are going to be hard to find .There are also voltage drop issues due to cabling that have been covered by others .You could easily get a say 50 watt SMPS at a higher voltage like say 12 or 24 .Now if you run a buck DCDC converter you can easily make your 6V .Place the buck converter close to the load to get full benefit of your reduced cabling losses.If you are in a hurry you could buy a buck converter and learn nothing .Otherwise you could get a schematic of a 5V buck and change it to 6V .There are lots of chips that will work with a small number of additional parts .Finally you could design your own with discretes and never have a badbeetle again.