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So I needed to find a value for a capacitor (Zx, where the resistive component is zero) to perform power factor correction (PF = 1) on the following circuit:

enter image description here

w = 1250

ZL = (98.1+157.5)+j(1250)(0.15) Rt = 1k

I calculated that I need a capacitor with value C = 1.032E-7F, so I used a 0.1uF cap and measured voltage waveforms of the source and load with the NI MyDaq (garbage, but we have to use it for our lab class.) I realized that I need to be looking at the current waveform though. I obtained the following waveform:

enter image description here

This shows the voltage of the capacitor/load node is in phase with the source. However, I have no way of measuring current. I know that i = C(dv/dt) for the capacitor. So the current waveform would be 90 degrees out of phase with both voltage waveforms. Similarly, the inductor equation for current (Zl has an inductor of L = 0.15 H,) has an integral so it introduces a phase shift.

My question is as follows:

Is looking at the voltage waveform for the inductor and capacitor and deducing the fact that each respective current's phase offset will cancel with the other enough to say that we actually have achieved a unity power factor?

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  • \$\begingroup\$ Given the two waveform you have for Vs and VzL, so what do you get with \$ \frac{V_S-V_{ZL}}{R_T} \$? So not only you can deduce that the current is in phase, you can actually get the current with a little calculation. \$\endgroup\$ – rioraxe Jan 25 '16 at 10:27
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No, you can't assume from the fact the the C & L current is 180 deg. out of phase -- you'd need to know the magnitude of each component's current also.

Else -- you could use any value of C & L and come to the same conclusion.

But since RT is real, and the voltage on each side is in pause, then the voltage across it is in phase ==> the current is in phase...

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  • \$\begingroup\$ Is that the best way to make the conclusion that PFC worked? \$\endgroup\$ – jonnyd42 Jan 25 '16 at 5:00

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