I'm not sure how the addition of the intrinsic region affects the built in potential of the diode. I also can't seem to find any information about it online. Thanks for the help.

How does the built in potential of a pin diode compare to a pn diode?

  • 2
    \$\begingroup\$ So what exactly is your question? Edit the question and don't post the question in the comments. \$\endgroup\$
    – Transistor
    Jan 28, 2016 at 19:56

1 Answer 1


The PIN diode will have the same barrier for the material; however, it will have a different frequency behavior. The N and the P regions are highly doped, take a standard band diagram and then stretch it out. The barrier height will be the the same.

I have used these devices as attenuators, and the low frequency behavior is identical, but at high frequency, they look much like a resistor.

I believe that there is a write up on them Andy Grove's "Physics and Technology of Semiconductor Devices"; however, I have not seen them described in detail anywhere else.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.