# How long will my battery last and how to calculate it? [duplicate]

This question already has an answer here:

I have a 12V 18Ah battery I wish to run through a boost converter at 40v and 2.5A to power a 100w led.

Could someone figure out how long my battery would power my led and show the calculatins/formulas.

Thanks

## marked as duplicate by Asmyldof, gbulmer, PeterJ, Brian Drummond, Olin LathropFeb 10 '16 at 11:47

• Besides that its impossible to do accurately without knowing the efficiency of the boost converter, why didn't the gazillion questions that handle the same topic here answer the question already? – PlasmaHH Feb 10 '16 at 10:00
• @PlasmaHH - that is essentially the same question and set of good answers. This question is a duplicate, and so should be closed. – gbulmer Feb 10 '16 at 10:44

Two methods:

Amp-hour calculation

Use formula

$$P = V \cdot I$$

For your load the power consumed is $P = 40 \cdot 2.5 = 100~W$ as you correctly identified.

If your boost converter is 100% efficient it will consume 100 W. Therefore $I = \frac {P}{V} = \frac {100}{12} = 8.3~A$.

Run time is then $\frac {18~Ah}{8.3~A} = 2.16~h$.

Watt-hour calculation

This is simpler. Your battery can supply $12~V \cdot 18~Ah = 216~Wh$. You have a 100 W load so you could run it for 2.16 h (if you had a 100% efficient booster).

Correct these calculations with the efficiency of the boost converter and add in some safety factor for deterioration of battery over time.

See @SteveG's comment below regarding de-rating for fast discharge.

• Presuming that this is a sealed lead acid battery, the 18Ah capacity is quoted for a 10h discharge. If you discharge it in 2h then the capacity is around 12.5Ah. The run-time becomes 12.5/8.3 = 1.5h. See the Discharge Characteristics in yuasabatteries.com/pdfs/NP_18_12_DataSheet.pdf – Steve G Feb 10 '16 at 10:28
• I forgot to include that. I've added a pointer to your comment. Thanks. – Transistor Feb 10 '16 at 10:35