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I'm struggling with evaluating this one:

\$(\overline ABC\oplus A\overline B) + (\overline AB)\$

I've got to

\$A\oplus B + A\overline B \overline C +\overline ABC\$

But how do I prove that \$A\overline B \overline C +\overline ABC = 0\$

Edit: The answer is \$A\oplus B\$

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    \$\begingroup\$ +1 for properly figuring out mathJax for boolean algebra. The anwering people can take an example from you. \$\endgroup\$
    – jippie
    Feb 12, 2016 at 20:18

2 Answers 2

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A⊕B is AB(Bar)+A(bar)B

So the Expanded equation is

AB(Bar)+A(bar)B+AB(bar)C(bar)+A(bar)BC

Taking Common factors out

A(bar)B(1+C(bar))+AB(bar)(1+C)

1+ anything is always 1

So we Have A(bar)B+AB(bar) which is A(exor)B

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    \$\begingroup\$ Always Welcome! \$\endgroup\$ Feb 12, 2016 at 11:00
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Here is the answer:

Image

Hope this help

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