So, I have to find the initial conditions for the following circuit with a switch. For \$t<0\$, the switch is closed, so we draw the inductor as a short circuit and the conductor as an open circuit. I have to find the voltage drop across the conductor, which would be equal to the voltage drop across the \$R_2\$ rezistor, as well as the current through the inductor.
Here comes the problem, since the current source \$J_2\$ is short circuited, how would I go about solving this? From what I know, the source wouldn't be eliminated and the current flowing through the short circuit would be equal to the source, \$i_L(0-) = 4 A\$. However, I'm not sure how I could go about finding the current flowing through the \$R_2\$ rezistor, as the current source parallel to the short circuit is confusing me.
Any input would be much appreciated. Thanks in advance!