Quiescent Power Dissipation in output Transistor

I'm trying to calculate the quiescent power dissipation in output transistors, the circuit below is part of a larger AB Amplifier circuit. I can't figure how to go about calculating the power dissipation. How can I calculate quiescent power dissipated in the transistors?

I know that power dissipated is Voltage drop across C-E junction times Collector Current, however cannot figure out how to find those values.

I'm assuming that by quiescent power dissipation it means when there is no input signal for the amplifier, correct me if I'm wrong.

• In the future you may want to include a question in your post for clarity. Also, there is a circuit editor/simulator fyi, just press the button. – Voltage Spike Mar 2 '16 at 17:55
• @laptop2d Sorry I thought it was clear, added it now. Thanks for the tip, didn't know about the editor. – user14492 Mar 2 '16 at 17:58
• Measure the voltage drop across the 1R resistor. Then use I = V/R to get current and P = V*I to get power. Although because the resistor is 1R, then the power is going to be equal to the voltage drop. For example, if you get 500 mV, the power would be 500 mW. – squarewav Mar 2 '16 at 22:34