I am having a galvanic cell with the following half cell equations:
Anode--> 2Al(s) + 6OH --> 2Al(OH)3 + 6e-
Cathode--> 6H+ + 6e- --> 3H2(g)
So my cell is producing 6 electrons. Is there a way to calculate the current (ampere) generated using 6 electrons, theoretically?
P.S. sorry for the bad formatting but when I tried OH$^-$, it did not give me OH superscript - as shown.