While studying about capacitors, I came across with an explanation talking about "jumping up and down when a capacitor separating two stages". I understood from several articles here that capacitors block DC when it is fully charged and that the idea of 'charging and discharging' of capacitor.
'This page' explains
- If a capacitor has the negative lead connected to the 0v rail, it will charge and discharge
- If a capacitor is NOT connected directly to the 0v rail, it will JUMP UP AND DOWN.
and with the following figure, says
the capacitor will 'fall'and the voltage on the negative lead can actually go below the 0V rail
where I totally lost my understanding.
(please refer to '4. A capacitor separates two stages' on 'the linked page.')
The pages explains that
By knowing how much a capacitor jumps-up-and-down, you can "see" a circuit working. and here my questions came.
- I can't understand the difference between 'charging/discharging' and 'jump up/down'. I thought even though it's not directly connected to 0V rail, still depending on its reference voltage, it can be charged and discharged. What is the difference in those two expression to comprehend their meaning?
- What happens when capacitor jump up and down?
- How can I calculate the amount of the 'jumps'?