Can somebody help me solve this. I need to find the equivalent resistance of these resistors. I really don't know where the trick here is. If somebody could help me I would really appreciate it enter image description here

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    \$\begingroup\$ If there is a 'trick' it is to redraw the circuits so that you can see the actual arrangement. With practice, you can do it in your head. \$\endgroup\$ – Spehro Pefhany Mar 16 '16 at 18:19
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    \$\begingroup\$ Was about to say that @SpehroPefhany \$\endgroup\$ – Jasser Mar 16 '16 at 18:20
  • \$\begingroup\$ Give each node a name and then try to redraw and simplify... \$\endgroup\$ – Jasser Mar 16 '16 at 18:21
  • \$\begingroup\$ And check your third one. Do you see anything tricky about the jumper? \$\endgroup\$ – WhatRoughBeast Mar 16 '16 at 18:46

You need to redraw the circuits, I did the first one. Then you can use regular circuit theory to combine resistance.


simulate this circuit – Schematic created using CircuitLab


First circuit: all resistors in parallel. (every is connected to A by one side and to B by other side)

Second circuit: first is in series with following 3 that are also in parallel. (almost same as first, only added one resistor before parallel)

Third: shorted (Rek=0) (A to B over diagonal short connect)

  • \$\begingroup\$ We prefer to rather give hints instead of outright answers to questions which are clearly homework. \$\endgroup\$ – brhans Mar 16 '16 at 18:21
  • \$\begingroup\$ I am sorry, I edited my answer. \$\endgroup\$ – Haris778 Mar 16 '16 at 18:22

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