# Finding Thevenin Impedance of a circuit

For this circuit, I am trying to find the equivalent Thevenin impedance by disabling the sources and calculating the resistance between points A and B. What happens after the voltage source is replaced with a wire? I have the current source being an open circuit so the capacitor and 2k resistor are in series, but does the wire contributed from the voltage source short this combination? If so, would the resulting equivalent resistance just be the two kilo ohms in the top left? Thanks for any help

• Impedance (not resistance) is the key term. How do you account for the effect of the capacitor? Mar 18, 2016 at 18:21
• Have you tried drawing the voltage source with a wire and then maybe moving components around (while keeping the same connections) to see if things are in parrallel or in series ? Mar 18, 2016 at 18:22
• I'm sorry, I don't really understand what can the capacitor do? I replaced the voltage source with a wire, and connected the resistor and capacitor in series to form an equivalent impedance, and this equivalent impedance is in parallel with a wire. Mar 18, 2016 at 18:50