I'm studying for an exam and as a part of a question I am given a transimpedance amplifier and need to explain/show how the current gets converted to voltage.
That's fairly easy, however, the op-amp has a Vb connected to the non-inverting input, which makes my answer differ from the official one.
My logic says that the inverting input is virtually on Vb, and then when we add the voltage drop over R1, output is V1 = Vb - I * R1
.
The official answer just says V1 = - I * R1
.
Is my understanding flawed? Does the non-ground reference affect the output?