# Why voltage source is not included while using KVL?

I would like to know why the voltage source is not used in the equation as given in this image below.

In the image the equation is:

$-I1∙8Ω+I2∙4Ω=0$

Why can't the equation be $10-I1∙8Ω+I2∙4Ω=0$ using KVL?

• Voltage source ?? I do not see a voltage source in this schematic. I do see a current source though. Apr 6, 2016 at 10:20
• @FakeMoustache:Oh that's right.That's why this doubt came.Now I can get the answer of user3219492.Should I delete this question? Apr 6, 2016 at 10:22
• @justin No, this is an acceptable question in that it shows an electronics problem, an attempted solution, and then a good corrected solution. Keeping it on the site would be worthwhile in my opinion. Apr 6, 2016 at 10:41