0
\$\begingroup\$

enter image description here

The above is the requirement, I have configured a circuit as shown below

schematic

simulate this circuit – Schematic created using CircuitLab

I have solved the above schematic using superposition and deduced that \$R_1:R_3 = 3:1\$, but I could not get the required output.

Superposition node voltages:

When \$V_1 = 0\$, $$V_{\text{node}} = \frac{R_2V_1}{R_1+R_2+R_1R_2}$$

When \$V_2 = 0\$, $$V_{\text{node}} = \frac{R_1V_2}{R_1+R_2+R_1R_2}$$

I have mapped the coefficients and deduced the above ratio.

\$\endgroup\$
2
\$\begingroup\$

Using superposition you can show that:

(R1||R2||R3)/R1 = 1/2

and

(R1||R2||R3)/R2 = 1/6

So if we set R1||R2||R3 = 10K (a more-or-less arbitrary choice)

R1 = 20K

R2 = 60K

R3 = 1/(1/10K - 1/20K - 1/60K) = 30K

Let's simulate it:

enter image description here

\$\endgroup\$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.