The circuit above is that of a buck regulator that has an efficiency of approx 85%. The input and output voltages are 10V and 3.3V resp. The output wattage is 0.2W.
So, the output current is Iout = Power/Voltage = 0.2/3.3 = 60mAmps.
Now, my doubt pertains to the current drawn from the battery or bench supply that gives/supplies the 10V.
Now, since the Pout=0.2W, Pin=0.23W (due to the 85% efficiency value). So, 0.03W is lost or dissipated in heat.
Now, Pin = 0.23W. So, I = 0.23/10 = 0.023Amps = 23mAmps. Is my deduction and understanding correct ?