I have got the following parameters for a buck regulator and am attempting to find a suitable inductor:

Vi = 3.6
Vo = 1.8
Imax = 1.5
Fsw = 56000
Iripple = 0.45

Plugging all these into the inductance value formula:

L = ((Vin - Vout) * Vout) / (Vin * Fsw * Iripple)
L = 35.714

I know I've got to consider the current ratings of the inductor (with the peak current of Imax + (Iripple / 2 ) = 1.725A). If I use this 1.725A and ensure the peak saturation of an inductor is above this (by some safety margin as well), do I still have to consider the RMS current of the inductor. If so, what minimum values should I be requiring considering the above parameters and how do I calculate them?


$$ Irms = Imax \sqrt{1 + (\frac{Iripple}{12 \times Imax})^2} $$ for a triangular wave (the type from continuous current mode).

|improve this answer|||||

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.