On this page, the two versions of this gyro/accelerometer IC have two different Logic Supply Voltages.

What is the VDD voltage?

Why would one version of the chip also have an option to make the voltage 1.8V?


enter image description here

note: not intended to be a dupe of What is the difference between \$V_{CC}\$, \$V_{DD}\$, \$V_{EE}\$, \$V_{SS}\$.


2 Answers 2


\$V_{DD}\$ is the supply voltage (i.e. the main voltage "in" to power the IC).

Quote from 1st the link you posted:

VDD Supply voltage range of 2.375V–3.46V; VLOGIC (MPU-6050) at 1.8V±5% or VDD

As for why there's the 1.8V VLOGIC version? I suppose it's for those that want to interface with a 1.8V \$I^2C\$ bus (as opposed to, say, 3.3V SPI or \$I^2C\$ as you'd likely use with the non-1.8V version).


From the data sheet:

For power supply flexibility, the MPU-60X0 operates from VDD power supply voltage range of 2.375V-3.46V. Additionally, the MPU-6050 provides a VLOGIC reference pin (in addition to its analog supply pin: VDD), which sets the logic levels of its I2C interface. The VLOGIC voltage may be 1.8V±5% or VDD.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.