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I'm planning on building a low-cost LED fixture and I'm a bit confused with how I should drive it. So, if we consider these 2 led cobs:

  • 1W 350mA 3.2-3.4V 100-110LM
  • 3W 700mA 3.2-3.4V 260-280LM

If I drive them both with a 300mA constant current driver, I have the following questions:

  1. Would the 3W led generate less heat?
  2. Would the 3W led generate more light? (lumens)
  3. Would the 3W led be less efficient? (lumens/watt)

For reference: leds, driver

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    \$\begingroup\$ imho, if you are that worried about this minutiously, you shouldn't be buying LEDs at AliExpress \$\endgroup\$ – Wesley Lee Apr 30 '16 at 20:05
  • \$\begingroup\$ Since there isn't a datasheet with proper graphs on the listing, you can look at other 1W~3W LEDs and estimate how much more or less efficience/light you would get: osram-os.com/Graphics/XPic5/00179585_0.pdf/LW%20W5SM.pdf \$\endgroup\$ – Wesley Lee Apr 30 '16 at 20:08
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It's impossible to know the behaviour at a current that is not the specified operating point if there's no datasheet containing an "intensity over I_f" graph – if this is of concern to you, buy LEDs that come with such a datasheet.

Yet another thing I'd like to point out that you don't say anything about your 300mA supply – it might look that an LED that is more efficient at 300mA would be the power-efficient choice, but if it happens to have a lower forward voltage at that current (is there at least an I/U graph?), you'll just "burn" that additional energy (voltage = energy per charge) in a linear regulator.

Now, it's really impossible to tell what kind of regulator you have picked there – yes, this looks a bit like the mains voltage gets rectified on the input side, and then chopped up and downconverted by the transformer type thingie there, but I can't tell the least about how exact the current regulation is (but I do have a hunch that without any secondary side sensing, it's not going to be that exact) or how efficient the conversion. So: if you're at all concerned about operational specifics of your LED system, this is not the supply of your choice.

Generally, people will sell their LEDs at the point at which they produce the maximal amount of light without thermal damage (or without exhaustion of recombination opportunities in the semiconductor), and that will be pretty close to the point of maximum efficiency. So, if you want to drive an LED specified for 700mA at 3.3V with less than its maximum power, you typically use PWM to switch it off and on with a configurable duty cycle, driving it at an "efficient" 700mA when on.

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  • \$\begingroup\$ Thanks! My biggest concern is heat, as I want to make a very slim fixture, so I wonder if buying higher rated LED COBs would help in that regard without losing too much light emission or efficiency (the difference in cost between 1W, 3W and even 5W is almost negligible) \$\endgroup\$ – Cay Apr 30 '16 at 21:29
  • \$\begingroup\$ "maximal amount of light without thermal damage (...) that will be pretty close to the point of maximum efficiency" - Not quite. A 3W LED will be more efficient at 1W than at 3W. What I think you meant is that manufacturers will try to drive the LEDs to maximum amount of brightness inspite of loss of efficiency. Thats why cheap LED bulbs heat so much and last so little compared to higher quality/more expensive ones. \$\endgroup\$ – Wesley Lee Apr 30 '16 at 21:47
  • \$\begingroup\$ p.s.: for the LED I mentioned in the questions comments, to double the luminous flux at 350mA you need 900mA, so efficiency definetively falls the harder you drive it. \$\endgroup\$ – Wesley Lee Apr 30 '16 at 21:51
  • \$\begingroup\$ Most of the charts I've seen show better efficiency at significantly lower outputs. For instance with these, my friend wanted to use 3 emitters at 3000ma, total for 30.0W. I suggested 7 emitters at 1050ma, yielding 3% more lumens at 21.6W. This was an application where heat mattered a lot and cost less so. cree.com/xlamp/hi \$\endgroup\$ – Harper - Reinstate Monica May 1 '16 at 0:44
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As a rule of thumb, leds are usually more efficient when run at lower powers (but not by a whole lot). The problem I think you're going to have is that the efficiency differences between manufacturers is going to be greater than between power levels. Some cheap leds can only do 40lm/w (even though they're advertised as 100lm/w) while some pricey cree leds can do 160lm/w. But what you will probably find is that the 1w and the 3w leds may actually use the same led chip. I used to work for a lighting company and we saw this all the time from cheap manufacturers.

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In my experience, LEDs are marketed at their maximum safe overdrive, but spec'd at their most efficient output, which is much lower.

Take this guy, advertised as 10W at its hard limit of 3000ma.

But all the specs in the sheet are based on driving it at 1050ma, which yields about 3.1W. This yields 400 lumens or an impressive 129lm/w (I'm reading out of bin V2, 85C which is conservative, other bins/temps go as high as 172 lm/w).

However running at the (advertised) hard limits of 3000ma, it only gives 91 lm/w. Whoops.

enter image description here

So in that case you get a 41% efficiency gain by driving the device gently. It's funny, the curve doesn't look that bent! But it is multiplied by the amp-volt graph, which is bent too. Try 480ma @ 2.78V (from the amp-volt graph)... 50% rated lumens so 200lm, @1.334w or 150 lm/w. Crazy. And that's the lowest bin, if we get into the high bins, low temps and underdrive, we could hit 200lm/w.

enter image description here

Having looked at quite a few LEDs, this is very typical. LEDs make heat for 2 reasons: being overdriven to get max lumens from minimum $ in emitters; and phosphors are inherently inefficient.

All things being equal you are better off driving the larger device at 1/3 power.

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