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\$C = 1 \mu F\$
\$L = 2.2 mH\$
\$r = 1.7 \Omega\$
\$f = 4000 Hz\$
\$V_{IN} = 2.6 V\$
I have this RLC circuit where I need to find \$V_{OUT}\$. I have tried it by finding the \$Q\$ factor and then multiplying it with \$V_{IN}\$ which gave me the value \$84.56427 V\$. However, when putting that value in as an answer in the system I'm using, I don't get the right answer, even if I round it up to \$84.6 V\$ or \$85 V\$.
What am I doing wrong?
You have a fixed frequency (4kHz), series RLC circuit with a constant peak Vin of 2.6V, so you can think of it as a voltage divider.
Work out your reactances at 4kHz and Vout will be proportional to Vin.
$$ X_C = \frac{1}{2\pi fC}\Omega = \frac{1}{2\pi(4000)(10^{-6})}\Omega$$ $$ X_L = {2\pi fL}\Omega = {2\pi(4000)(2.2\times10^{-3})}\Omega$$ $$ V_{OUT} = V_{IN}\frac{(X_L+R)}{(X_L+X_C+R)} $$
Hope this helps!
