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This is homework. I've tried my best to find the best answer that I could understand and could be accepted by my lecturer.

  1. I've searched my lecture notes, wiki and google to find some good explanation defining solar irradiance. But somehow I still don't understand how I should 'define solar irradiance'. Can someone give me a few good sentences explaining solar irradiance.

  2. What are the changes, if any, in a photovoltaic cell (in terms of short-circuit current and open-circuit voltage) if the irradiance is reduced by 50%?

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  • \$\begingroup\$ Isn't it just a measure of the amount of sunlight (e.g. photonic energy) striking a specific area (typically 1^2 meters)? What are you confused by? \$\endgroup\$ – Connor Wolf Dec 8 '11 at 12:25
  • \$\begingroup\$ @Fake Name Because my lecturer gave me a question on 'Define solar irradiance' on my coming test but i can't seems to find an answer to suit my own understanding and a answer that he could accept.. Can be explained by "solar irradiance is a measure of the amount of sunlight striking a specific area of the solar cell"? \$\endgroup\$ – Imso Dec 8 '11 at 12:35
  • \$\begingroup\$ I would say more along the lines of "The amount of solar energy per unit area". You may also be interested in the term insolation, which I believe is pretty much synonymous with solar irradiance. \$\endgroup\$ – Connor Wolf Dec 8 '11 at 12:44
  • \$\begingroup\$ @FakeName For question 2 i understand that the open-circuit voltage will stay the same but the short-circuit current will drop approximately by half? Is that correct? \$\endgroup\$ – Imso Dec 8 '11 at 14:01
  • \$\begingroup\$ This forum is not here to directly solve homework problems, but to answer specific questions (non-homework), solve problems, and to better understand electronics and related concepts. Here and in (@Olin)'s answer you ask someone to answer #2, but the information is already there. \$\endgroup\$ – Joshua Dec 8 '11 at 14:46
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Just looking at the graphs and understanding them will greatly increase your knowledge.

  • The last two graphs answer your questions about what happens to voltage and current as light levels change.

  • The black body and irradiance curves will show you how the irradiance is made up spectrally, what sort of results occur and the effects of the atmosphere


Lot's of related and useful material below, but a summary is:

  • Solar irradiance is the amount of sunshine falling on a surface BUT in the Photovoltaic (PV) panel context, this is measured relative to two main standard measures - based on energy incidence and wavelength distribution.

    • The standard level of solar energy incidence at the earth's surface = "One sun" of solar insolation which is defined as 1000 Watts per square meter of irradiance under spectral conditions as defined by Am1.5 (= Air mass 1.5 - see below) at 25 degrees C.

    • The standard measure of spectral distribution comes in two forms - one for typical PV cells which are usually pointed at or near the sun and which receive about 1 sun max insolation on the surface, and the other is for "concentrator cells" which use dishes or lenses or mirrors to concentrate the sun. I won't say much more about Concentrator cells except that they may receive energy from about the whole sky surface at once so some light comes from very long paths through the air and some by much shorter ones. This mix of paths changes the spectral distribution of the light received. Amount of light available.

    Absorbtion of spectral energy at different wavelengths depends on the mount of air that the light has passed through an what else was in the air (water, CO2, ...).

    Air Mass 0 = AM0 is the condition in space where there is NO air.

    = Air Mass 1 = AM1 is the condition when panels point straight up and the mass of air is the shortest possible from surface to space.

    Air Mass 1.5 = AM1.5 is the mass of air when the light comes through the atmosphere such that there is 1.5 x as much air in thr path as when the panel points straight up. AM1.5 usually is taken as occurring at panel angle = 45 degrees to vertical.
    This is the measure most usually used for PV panel measurements.


Be aware of the fantastic Gaisma site http://www.gaisma.com . A large numbero of locations on earth have their own page such as eg Nairobi, Kenya http://www.gaisma.com/en/location/nairobi.html

Learn how to use the graphs there. For Nairobi here is the table which tells you what to expect month by month. Monthly mean irradiance peaks at 6.44 kW-hour per square meter per day. in February and 4.4 hours per day in July.

enter image description here


Actual above atmospehere insolation is about 1.35 kW/m^2 and at surface it varies with location and season and time of day - at midday in some locations is usefully above 1000 W/m^2.

The Am1.5 conditiin is related to the typical path through the atmosphere which causes absorption of some wavelengths more than others.

The Wikipedia page on air mass explains the Am1.5 condition thus -

  • The air mass coefficient defines the direct optical path length through the Earth's atmosphere, expressed as a ratio relative to the path length vertically upwards, i.e. at the zenith. The air mass coefficient can be used to help characterize the solar spectrum after solar radiation has traveled through the atmosphere.

    The air mass coefficient is commonly used to characterize the performance of solar cells under standardized conditions, and is often referred to using the syntax "AM" followed by a number. "AM1.5" is almost universal when characterizing terrestrial power-generating panels.

The irradiation level with wavelength above the atmosphere closely but not perfectly follows that of a black body radiator.In the diagram below the greay crve is the amplitude with wavelength for apefect black body radiator and the yellow-orange curve is solar output.

Graph 1 - Black body radiation curve compared to solar output in space

enter image description here

After the light has travelled through the atmosphere the spectral levels will be modified as shown below.As can be seen from the labels, atmospheric water causes a number of absorbtion areas,ozone causes losses in the UV area and oxygen abd co2 also have absobtion lib=nes. - This is in addition to gross degradation of level due to the partial opacity of the air at all wavelengths.

Here are some sites related to AM1.5 issues.

ASTM .

Table of standard AM1.5 response in 0.5nm wavelength steps !!!

Here the PVeducation.org site introduce AM0 and AM1.5 "direct and circummslar spectrum](http://pveducation.org/pvcdrom/appendicies/standard-solar-spectra) for concentrator use.

Solarlux - more of the same, but useful

Graph 2 - Solar radiation received at earth surface (red) and in near-earth space outside the atmosphere (yellow).

enter image description here


PV panel CURRENT output varies APPROXIMATELY linearly with insolation level as per graph below.

enter image description here

http://www.altestore.com/howto/images/article/IV_curve.jpg


Even more useful is this curve:

As well as the V-I plots, which show the decrease in current with decreasing light level, it shows power versus voltage curves (dashed lines) which show how power varies as you trace along one of the smooth lines. Towards the lef side you have heavy loads and high current but low voltage so low power. As you decrease loading voltage rises so power rises. As load continues to decrease power approaches a peak value and the falls rapidly as load is furthr reduced. The peak of the power cure is called the MPP = Maximum power point. Note that as light levels drop the power peak moves diagonally to the left and down. Devices which maintain the panel at optimum load to keep output at a Maximum as light changes are called MPPT = Maximum Power Point Tracking controllers.

enter image description here

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Solar irradiance, often referred to as "insolation" in solar cell documentation is simply a measure of how much light is hitting the solar cell. Often for solar cells this is described in units of relative to "full sunlight". Usually a formal definition of this is not given, but for purposes of sizing solar panels and understanding the insolation required for a particular setup, a few percent shouldn't be a issue. If you're that close, you're too close anyway.

In the tropics with the sun directly overhead with a clear sky and a black body directly facing the sun, insolation is about 1.2 kW per square meter although figures for even that vary somewhat. Things are rarely that perfect, so 1 kW per square meter is considered a reasonable rule of thumb what "full sunlight" means. Another way to describe brightness is lux, although that is aimed at describing visible brightness. The two aren't necessarily the same due to color content. However, you can relate the two by stipulating "sunlight" or sometimes the particular color temperature of the sun. In any case, daylight is about 100,000 lux, but again, this sort of figure is rarely used when dealing with solar cells. It is more appropriate when dealing with light sensors, not when trying to get meaningful power from the light.

A solar cell is basically a diode. When a photon hits the right way in the depletion region of this diode, it knocks things loose to let a finite charge flow. Current is therefore mostly proportional to insolation, although it depends on the voltage somewhat. The short circuit current is what you get when the voltage is externally held at 0. Then current is quite proportional to insolation, but you get no power out since power is voltage times current and the voltage is zero.

Being a diode, the voltage is reasonably insensitive to the current to a point. The voltage and current relationship is definitely not linear like a resistor. Maximum power, which is maximum area of the rectangle on a voltage x current graph, usually occurs somewhere around 80-90% of the open circuit voltage. The open circuit voltage also changes a bit with insolation, which is why there are such things as "maximum power point tracking" to insure the best operating point is used for the current conditions. These include temperature. The diode voltage goes down with temperature but the current is largely uneffected. This is why solar cells are more efficient at lower temperature.

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  • \$\begingroup\$ Hi thanks for answering very insightful explanation indeed! But lets say given a question like "what are the changes if any, in photovoltaic cell short-circuit and open voltage if the irradiance reduces by 50%"? How should i explain this question? \$\endgroup\$ – Imso Dec 8 '11 at 13:45
  • \$\begingroup\$ i understand that the open-circuit voltage will stay the same but the short-circuit current will drop approximately by half? Is that correct? \$\endgroup\$ – Imso Dec 8 '11 at 14:00
  • \$\begingroup\$ @Imso: Short circuit current is pretty proprotional to light, so if irradianse drops by half the short circuit current will drop by half. Open circuit voltage does vary with light, but only a little. It will go down under half the light, but a lot less than by half the voltage. You are essentially on a diode exponential curve at that point. \$\endgroup\$ – Olin Lathrop Dec 8 '11 at 15:32
  • \$\begingroup\$ Needs more pictures/cowbell. +0.5 ;) \$\endgroup\$ – tyblu Dec 10 '11 at 16:40
  • \$\begingroup\$ @tyblu: Huh? Cowbel? \$\endgroup\$ – Olin Lathrop Dec 10 '11 at 17:47
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Irradiance is defined as the flux of radiative energy per unit area incident on a surface, measured in W/m2 in SI units. It is in fact the photon flux at the surface of the solar cell and so it strongly impacts short-circuit current but open-circuit voltage to a lesser degree.

For a 50% photon flux we would expect approximately 50% drop in current and a very slight drop in voltage (see image below [source])

photocell current vs. voltage at various irradiances

Technically irradiance and insolation are not the same thing. Insolation is the irradiance of the sun (i.e.: specific to solar physics).

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  • \$\begingroup\$ So it can i explain it in "Solar irradiance is a measure of the amount of solar energy per unit area reaching the surface of a solar cell measured in W/m^2"? Do correct me if i'm wrong or need amendment in the way i phase it! BEcause i sort of want to explain in my own understanding.. Thanks! \$\endgroup\$ – Imso Dec 8 '11 at 14:26
  • \$\begingroup\$ @Imso seek and thy shall find ;) en.wikipedia.org/wiki/Irradiance en.wikipedia.org/wiki/Insolation \$\endgroup\$ – klonq Dec 8 '11 at 14:41
  • \$\begingroup\$ actually it's the amount of solar anergy per unit area per unit time... \$\endgroup\$ – vicatcu Dec 8 '11 at 20:40
  • \$\begingroup\$ @vicatu "flux" implies the time dependence. With irradiance being either energy per unit time per unit area, power per unit area or energy flux per unit area all being equal. \$\endgroup\$ – klonq Dec 9 '11 at 8:29
  • \$\begingroup\$ @klonq I'm confused here.. Sorry for my slow absorption rate of what you wrote up there? So i should rephrase it as "Solar irradiance is a measure of the amount of solar energy flux per unit area reaching the surface of a solar cell measured in W/m^2"? \$\endgroup\$ – Imso Dec 9 '11 at 11:23

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