Energy transfer in an inductive heater happens only due to the coupling of the primary inductance with the secondary load, which appears as a weakly coupled inductive load with a near-dead-short across the coil.
You can see an attempt to reverse-engineer a commercially available induction cooker here, which includes a SPICE simulation.
The inductive heating element is modelled like so:
simulate this circuit – Schematic created using CircuitLab
Note that K1 here (the coupling between L1, the primary coil and L2, the load model) is 0.99 - i.e. very strongly coupled. I am not sure why this model was chosen - there is no evidence of it having been measured. To then find the power being transferred, you can simply measure the RMS power in the heating load.
As a side-note - to calculate the real power being dissipated in the inductor in your circuit, you need to calculate the average of the instantaneous power dissipation over a whole number of cycles (as it seems you have almost done in the green power graph - make sure you average over an integer number of peak-to-peak or trough-to-trough cycles, not the 11.5 cycles you have in that diagram). You will find it is a low number (all your real power is dissipated in that sharp peak) - and this makes sense, because there is no load in your schematic.