Above is an example of 50 ohm impedance matching when using a pulse generator. As you see, adding a small shunt resistor Rs here for a very big load resistor adjust the equivalent resistor around 50 Ohm, hence the impedance is matched.
My question is as follows:
I have a function generator and sometimes it is used to output sharp pulses with 10V amplitude.
In that case imagine the generator output is coupled to a load with a quite high resistor like 1GigaOhm. For impedance matching I can then set the Rs as 50 ohm. So far so good.
But now Rs will see around 10V/50Ohm = 200mA for a 99% duty cycle pulse. This corresponds 0.2*0.2*50 = 2 Watt power dissipation.
Wouldn't a usual 50ohm resistor burn out in this case?
Moreover, how can one achieve impedance matching in this case?