I'm learning electronics and this confused me. In this circuit it shows that current flows through both wires with resistors and lower only through one wire where there's no resistor (even though one is with really low resistance). I thought current should still flow, what's happening here?
The old saying that "electricity follows the lowest resistance path" or whatever the case may be, is misleading. In true fact, parallel resistances form a current divider with each "leg" of the circuit carrying a current inversely proportional to the resistance. So, while a lower value resistance will carry more current than it's higher resistance neighbor, both will still carry some current. In the case of ideal circuit analysis, wires (and switches) have zero resistance. By evaluating the current divider formula as a resistance approaches zero, you can see that that leg will conduct a share of current that approaches 100%.
In summary, you are correct that in the real world, nothing is ideal and zero resistance is impossible. This means that some tiny current will be flowing through the 600 ohm and 1 ohm resistors, with the majority of it flowing through the closed switch. However, the current in the resistors is going to be so small it doesn't matter in practically any circuit.
When drawing a schematic like you have done in your simulator, connecting one point to another point directly is you telling the simulator that these are actually the same point in the circuit.
You are not telling it, "I have a wire of some length and non-zero resistance connecting these points".
For the circuit you've drawn, the simulator sees something more like this:
Its entirely possible that the simulator just optimizes away those 2 resistors because it knows that they will have no effect on the circuit, but even if it doesn't - just apply some simple Ohm's law to the situation.
The 2 ends of either of those resistors are connected to the same point. You need two different points to have a voltage difference, but you don't have that.
So you have 0V across the resistors and the current through them must also be 0A.