# Understanding why voltage and current sources are to be divided by s in the frequency domain

I have been told that whenever I'm drawing a circuit in the frequency (s) domain, the voltage source is to be replaced by V/s and the current source by I/s.

But what exactly is the reason?

When I'm plotting this circuit (replacing s with rad/s), I get that the voltage across R is decreasing as the frequency increase. intuitively, I would say that the voltage or current source should only have a frequency component at s=0, and 0 everywhere else, instead we have that as s approaches 0, the value of the voltage or current source approaches $\infty$ .

simulate this circuit – Schematic created using CircuitLab

It's because the Laplace transform is: $$A \to \dfrac{A}{s}$$
You assume that the source is applied at t=0: $$\int_{0}^{\infty} A e^{-st} \, dt = \frac{A}{s}$$