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I am new in VHDL. The code below doesn't work for some reason. The D0 and D1 are switches and when I added the D1 it stopped working. clk_Centi is pointing to an LED.

end if;
end process gen_clk;

    clk_Centi <= clk_Centi_i WHEN D0='0' AND D1='0' ELSE
            clk_Sec_i WHEN D0='1' AND D1='0' ELSE
            clk_Min_i WHEN D0='0' AND D1='1';

end Behavioral;
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In VHDL, you have to take into account every possibilities in a combinatory block for the program to work properly. I think that if you add a line with

WHEN D0='1' AND D1='1'

It will work again.

| improve this answer | |
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  • \$\begingroup\$ Easier way is to delete the last WHEN expression which will then cover all the bases for you. \$\endgroup\$ – Brian Drummond May 29 '16 at 21:42
  • \$\begingroup\$ When D0=1 and D1=1 (the state I didn't take into account) my output should be -. Is there a way to state this in VHDL? \$\endgroup\$ – traveller May 30 '16 at 3:50
  • \$\begingroup\$ Brians solution should work here without having to care about solving this - with D0=1 and D1=1 it will act like D0=0 and D1=1. Or maybe you do not want it to act like this. \$\endgroup\$ – Albits May 30 '16 at 7:44
  • \$\begingroup\$ I should match this case as zero as this will be the output of some leds. \$\endgroup\$ – traveller May 30 '16 at 8:31

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