I'm trying to calculate the transfer function of this high pass filter :
So basically I'm trying to find how I can find \$V_{\text{out}}\$.
Due to the amplifier we know that $$V_{in} = V_{\text{out}}$$ I know how to calculate \$V_{\text{in}}\$ but I can't seem to find \$V_{\text{out}}\$ because I am supposed to find this transfer function (since it is a Butterworth high pass filter):
$$|H_{ph}(j \omega)| = \frac{1}{\sqrt{1+ \left(\frac{\omega_c}{\omega}\right)^{2n}}} = \frac{\left(\frac{\omega}{\omega_c}\right)^{n}}{\sqrt{1+ \left(\frac{\omega}{\omega_c}\right)^{2n}}}$$
here \$n=1\$ because it's a first order filter
So I was wondering if any of you could help me and find this transfer function knowing that:
$$\underline{H}(j\omega) = \frac{\underline{V}_{\text{out}}}{\underline{V}_{\text{in}}}$$