I'm doing a course project on electrical engineering subject. I have to use this specific DC DC converter ISL2412 XP Power DC DC converter. But before I can use it, I have to explain how does it work.
I can't find anything about it's operating principle. The only thing I found out is that it isolated type. So this type of DC DC converters has galvanic isolation, is that the main part of it that do voltage transform?
So the question is, what is the isolated DC DC converter operating principle?
While it may not apply to the specific device from XP Power, application note slyt211 from Texas Instruments explains how small (<5W) isolated power converters such as the DCP010512 operate. Essentially, inside the converter, there is a set of switches and an isolation power transformer. The controller generates a waveform that allows for power to be rectified on the isolated side. An unregulated device has an internal diagram such as:
However, the ISL2412 you wish to use has regulated outputs. This adds additional complexity to the device. The LTM8048 datasheet shows how such a regulator could be implemented, along with the other switching electronics:
For dual-supply operation, Murata's BEI15 Series includes a block diagram for regulated outputs:
Further, Digikey reveals that this BEI15 Series module is not encapsulated, allowing you to see how components are arranged:
Here, you can see the control IC on the load side in the front-left of the module, the board-level transformer in the middle of the board with a snap-in ferrite core with the Murata logo, and two switching devices along with ceramic capacitors on the far edge of the device.
Finally, the Murata BWR Series devices includes a nearly complete diagram of a higher power (ca. 30W) isolated converter using synchronous rectification on the load side:
Additional references:
