When sending a dominant bit (0bit) on the CAN bus, I understand that CAN transceivers output CANH=3.5V and CANL=1.5V.
But when looking at the schematics of a CAN transceiver, I do not understand how the CANH=3.5V is achieved (figure as follows borrowed fro TI blog post).
Does the Schottky diode (in the picture) along with the transistor make the 1.5V drop? Based on the fact that Schottky diodes drop very low voltage (~0.5V), I can't imagine the MOSFET dropping 1.0V. Especially when the drain-to-source resistance is a few mOhms for CAN transceivers.
Anyone can explain how the 1.5V drop from Vcc=5V to CANH=3.5V is achieved?