Open Delta yields 57% of power instead of the 86% it would yield if no 30-degree angle gets in the way. Can that 30-degree angle be corrected with a capacitor and an inductor (it requires a cap in one phase and an inductor in the other phase)?? (it behaves like a power factor which is not caused by a load -- assume a resistive load).

This is a common question for those using power transmission systems. The two part question is: 1. Why can't an open delta with deliver two-thirds of the power of a balanced delta, if the loads are the same on the two remaining windings? and 2. Can this power be achieved by the addition of reactive components?

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    \$\begingroup\$ Can you clarify your question? This seems like an interesting question, but I don't understand exactly what you're asking. \$\endgroup\$ – user2943160 Jun 10 '16 at 1:09
  • \$\begingroup\$ Yep, a schematic or a reference would be helpful! \$\endgroup\$ – Dmitry Grigoryev Jun 10 '16 at 12:30
  • \$\begingroup\$ This question seems clear and understandable. \$\endgroup\$ – John Birckhead Jun 10 '16 at 13:29

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