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"Power consumption of common cathode is lower than common anode about 30%"

Is it right?

enter image description here

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closed as unclear what you're asking by Bence Kaulics, DoxyLover, PeterJ, dim, Dmitry Grigoryev Jun 17 '16 at 10:26

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    \$\begingroup\$ How could there be any difference? Please explain. \$\endgroup\$ – Roger Rowland Jun 17 '16 at 6:46
  • \$\begingroup\$ Where did the statement come from? There may be some context behind it. Assuming the same supply voltage, same base LED devices and the same resistors, the power will be the same. \$\endgroup\$ – Peter Smith Jun 17 '16 at 6:48
  • \$\begingroup\$ Haven't you already asked the question? The schematics are unnecessary. Better would be to tell us where you have heard that. Because as it is, it is wrong, but maybe there was some particular context in which it was right, but we can't know. \$\endgroup\$ – dim Jun 17 '16 at 7:24
  • \$\begingroup\$ With your schematics the answer is, obviously, not. But if the circuit is arranged like in this question maybe the power dissipated on resistor is different because there isn't the resistor! \$\endgroup\$ – Antonio Jun 21 '16 at 9:42
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Is it right? No it is not

It is utter nonsense stated by someone who obviously knows nothing about LEDs and/or electronics.

From the LED's point of view, they don't even "know" how they're connected.

Maybe the person who made the statement compared a 20 years old common cathode to a brand new common anode. Sure in 20 years LED efficiency has improved but that is unrelated to the way the LEDs are connected.

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  • \$\begingroup\$ Thank's for reply. Then, in captured image, how to calculate power consumption? \$\endgroup\$ – ryan Jun 17 '16 at 7:34
  • \$\begingroup\$ Power is voltage x current so measure both and calculate. \$\endgroup\$ – Bimpelrekkie Jun 17 '16 at 7:42

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