The owner of a broken washing machine recently asked me to examine a damaged circuit board he had found inside. Using the schematic I was able to determine that the charred area formerly contained a device labeled MOV. I found several of these devices on the board and now gather they were Metal Oxide Varistors, which can be used for over voltage protection.

Considering this board appeared to be a low power supply of some sort (transformer, rectifier, transistor etc.) and also contained a blown 0.5A fuse, what was the most likely function of the blown MOV?

In general, what are MOVs used for in PCB designs? Real world circuit examples would be great.

  • 1
    \$\begingroup\$ I think you meant MOVs, not varistors in general. A varistor is a broader concept, including essentially any varying resistor. MOV is one type of varistor. \$\endgroup\$
    – pipe
    Commented Jun 22, 2016 at 1:12

3 Answers 3


A varistor after the fuse ensures that when the voltage crosses a certain value, the fuse blows and current flow stops. Generally fuses are rated for a current limitation, not a voltage limitation (as in your example). It is possible that the voltage difference across the fuse is such that it doesn't create more than the rated current through the fuse yet is still such that it could cause harm to harm the circuit (or is just unwanted). In that case the varistor is used to increase current through the fuse, causing it to blow and stop the current. When the voltage crosses the upper limit, the varistor resistance is reduced, increasing current through the fuse as in this circuit:

enter image description here

Many PCB circuits contain inductors and capacitors which will create transient states and surges (switching spikes). Too much of this kind of occurrence will harm the device, so varistors are used for protection.


In the case of your circuit board, it sounds like your MOV decided to go low-impedance, meaning its internal resistance went close to zero and caused a big current to go through it, thereby overheating it and blowing it up. The current surge caused by the MOV doing this probably caused your fuse to blow. This was caused either by a large voltage surge that the MOV tried to shunt to ground, or the MOV was defective (either through manufacturing or over-used).

When used for circuit protection, MOVs are used to shunt excess energy to ground. Other devices that do this are gas discharge tubes and TVS diodes. Each has their own method of dumping energy, which is usually a trade-off between the accuracy of the voltage threshold (Vtrip) before dumping energy to ground versus how much energy the device can dump before it explodes.

You may see combinations of tubes, MOVs and TVSs on input circuits to protect them from surges, whether it be a power mains surge or lightning-induced effect. A rule of thumb for these circuits is delay-dump, where circuit blocks try to alternately delay or retard the surge (through inline devices like transformers, resistors, etc), followed by dumping it to ground through a gas discharge tube, MOV or TVS, and repeating these stages until the sensitive circuits behind the protection stages are reasonably safe. It's all about trying to handle and manage the excess energy while the protection circuit tries to shed it.

MOVs can get "old" due to exposure to repeated excess voltage and either fail or no longer function properly. Think of it as if the MOV has a counter inside of it for how many joules it can dump through itself before it is finished. I recall from my avionics years that MOVs were being avoided because of their indeterminate lifespan and lack of test methods to see if it was still functional.

  • 2
    \$\begingroup\$ In testing large 40mm MOV's for UL they had to pass 5,000 surges at 10KA with a 8uS/20uS pulse, spaced in groups of 3 which were 5 minutes apart. Each group of 3 was 30 minutes apart. Once done their 1mA clamp voltage was tested to see if it changed by more than 10%. If so it failed the test. We had very few failures. \$\endgroup\$
    – user105652
    Commented Jun 21, 2016 at 23:15
  • 1
    \$\begingroup\$ An 8uS pulse of 10KA implies a fearsome signal rise/fall time - I'm curious as to how those were generated? \$\endgroup\$
    – pjc50
    Commented Jun 22, 2016 at 15:23
  • \$\begingroup\$ @pjc50: capacitor bank with an SCR with a low inductance path to the DUT? \$\endgroup\$
    – akohlsmith
    Commented Jul 28, 2016 at 17:19

The varistor is used to suppress transients such as surges, switching spikes, and ESD events -- usually, they are found on power lines. Varistors absorb some energy every time they suppress a surge, and this reduces their voltage withstanding capability slightly -- too much of this, and the varistor turns on all the time, leading to an effective short across the line, no more varistor, and a blown fuse. Better that than sacrificing more costly components downstream, though!


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