NOTE! The LDR has a minimum val = 2kOhm and a max. val. = about 5 MOhm
Im trying to build this circuit for my radio station. I would appreciate som help.
- Your general opinion about the functionality of the circuit. (It is my first completely own-made circuit)
- Some thoughts, let me explain.
Well basically I have more than one question, but lets start with the main focus. So the whole idea of using the Zenerdiode is that I want that when the light is of (the LDR is attached to a tiny LED-lamp on the mixerbord, wich goes on if someone is calling the radio station) and the LDR has a value about 5 MegaOhm, there is not enough voltage over the Zenerdiode, making it act as a open (no current passing through). In that case, in my opinion, there will be no current and likewise no potential relative to ground in the point between the diode and R2. This would close the transistor. No light on the mixerboad, no LED1 2 or 3 is lit.
In the case where the mixerboard LED is on, well the potential after the LDR is much higher (hopefully around 7-8[V]) so the Zenerdiode will now push trough current, and the potential after the zener will appear. This will open the transistor and the LED's will be lit.
My main problem, and the reason why I designed it like this is because it is really important that the transistor is acutally "closed", and the LEDs are not lit when they are expected to not be lit. Basically, I tried to quantify a "light on" (on the mixerboard) with a specific voltage on the gatepin of the transistor, via the zenerdiod.
Is this viable?