enter image description here

It's the 6-pin SOIC in the middle with what looks like "67T" or "T76" on the top. I can't find any info on this I'm hoping someone here has come across this. The top left pin is possibly a digital I/O pin but that's all the info I have. Any ideas on how to trace this?

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    \$\begingroup\$ Need some more info - a broader shot of the circuit to get some context would be useful. \$\endgroup\$ Jun 29, 2016 at 21:42
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    \$\begingroup\$ The fact that the silkscreen legends are D6,D7 suggests they are diode networks, as a starting point. You can confirm this and work out the internal topology with a multimeter. Perhaps protection diodes for external I/O? The dots might indicate cathodes. \$\endgroup\$
    – user16324
    Jun 29, 2016 at 21:43
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    \$\begingroup\$ Also, it's more likely a SOT23-6 package rather than a SOIC. \$\endgroup\$ Jun 29, 2016 at 21:58
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    \$\begingroup\$ Not just a broader image of the board, but also a description of what this board does and where in the circuit this component is. \$\endgroup\$ Jun 29, 2016 at 23:43

1 Answer 1


From the looks of it, it could be a TVS (fits with the 'D' designator). Specifically the NUP4302MR6.

The device is a TSOP-6 package (similar to a SOT23-6 but a little smaller).

From the datasheet above, we see that the package markings are as follows:

Package Markings

The main marking is "67" as expected, followed by a letter representing the date code (in your case T). Note that it also specifies that the orientation of the date code may vary, so fine with it being at 90 degrees.

Also there is a dot indicating P1 and a second dot indicating lead-free. Your package has both dots in the expected locations (the Pb-free dot can be in one of two locations, yours is in the lower one by pin 2).

The pin locations also seem to fit with your circuit. The four corners seem to symmetrically go to resistors (or at least parts marked with R# designators). The centre pins disappear off through vias to another layer - presumably to power rails if it is indeed this TVS in that circuit.

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    \$\begingroup\$ Awesome answer, you should get paid for this. \$\endgroup\$
    – KalleMP
    Jun 30, 2016 at 7:11

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