2
\$\begingroup\$

Antenna's have a rated bandwidth of frequencies on which they operate. I understand that the antenna will still operate outside these frequencies, just that the signal will experience a greater attenuation at frequencies outside this range (like a filter's passband). Hence, my question is not a duplicate of this one.

What physical factor affects the bandwidth of an antenna? Is it the material? The image below shows two SMA compatible antennas. Both are almost the same length. The shape of the grey covering of the second antenna suggests that there is a similar inductor like structure inside it, which I know from practical experience is the "gain" of the antenna (correct me if I'm wrong).

The grey antenna is for 2.4 GHz WiFi while the black one is for sub 1 GHz GSM.

I can't seem to find out what physical factor affects the bandwidth. The only option left seems to be the material. Is it the case?

Also, since both have the same shape, is it safe to assume that both of them have the same polarization and radiation pattern? (I'm not good at Physics, avoid downvoting me on this). I don't know the model of any of these antennas however a Pulse W5017 antenna (not shown here) with the same shape has an Omnidirectional polarization and a Figure-8 radiation pattern according to it's datasheet (also shown below). Is it safe to assume that these antennas will have it likewise?

Antennas

Radiation Pattern of identical Pulse W5017:

Radiation Pattern of identical Pulse W5017

\$\endgroup\$
1
  • \$\begingroup\$ The gray antenna may have two or three separate radiating elements stacked end-to-end, to increase the gain at right angles to the antenna. \$\endgroup\$ Jul 11, 2016 at 16:24

1 Answer 1

7
\$\begingroup\$

There are hundreds of different antennas so for my simple attempt at an answer I'll concentrate on the "dipole" and I'm not going to go into formulas too much.

What physical factor affects the bandwidth of an antenna?

The impedance presented by the antenna is a major factor. If that impedance changes with frequency, then transmitted power will also change. Consider this: -

enter image description here

As dipole length becomes about half a wavelength the impedance becomes real and about 70 ohms. But go to 1 wavelength and the real impedance becomes infinite. This is a severe factor affecting bandwidth. Given also that the imaginary impedance change is quite severe, using a physical impedance (a series inductor for instance) to allow effective operation at slightly off exactly one half wavelength will result in a significant tightening of the bandwidth.

So, a short answer is that bandwidth depends on how you use the antenna as well as the choice of antenna.

There is a useful video at antenna.com on this page that might give a bit more insight. The same website goes on to discuss how thickening the dipole wire can make bandwidth wider: -

enter image description here

enter image description here

It now talks about VSWR (which is still all about the impedance presented by the antenna) and shows that a thicker wire produces wider bandwidth and, if the analysis spectrum were widened you would see much more significant effects: -

enter image description here

Antenna.com's conclusion below this is: -

Hence, this page can be summed up very succinctly: to get wider bandwidth, fatten up your antennas (this means: use more volume).

It's a really big subject but, for most regular antennas, the biggest decider of bandwidth is the driving electronics and impedance resonances. For instance, using a "short" dipole antenna antenna.com gives the following formulas and worked example: -

enter image description here

enter image description here

enter image description here

enter image description here

As an example, assume that the radius is 0.001 wavelength and the length is 0.05 \$\lambda\$. Suppose further that this antenna is to operate at f=3 MHz, and that the metal is copper, so that the conductivity is 59,600,000 S/m.

The radiation resistance is calculated to be 0.49 Ohms. The loss resistance is found to be 4.83 mOhms (milli-Ohms), which is approximatley negligible when compared to the radiation resistance. However, the reactance is 1695 Ohms, so that the input resistance is Z=0.49 + j1695. Hence, this antenna would be very difficult to have proper impedance matching. Even if the reactance could be properly cancelled out, very little power would be delivered from a 50 Ohm source to a 0.49 Ohm load.

For short dipole antennas that are smaller fractions of a wavelength, the radiation resistance becomes smaller than the loss resistance, and consequently this antenna can be very inefficient.

The bandwidth for short dipoles is difficult to define. The input impedance varies wildly with frequency because of the reactance component of the input impedance. Hence, these antennas are typically used in narrowband applications.

\$\endgroup\$
2
  • \$\begingroup\$ StackExchange doesn't like it, but I have to say thanks for this post :) Thank you! \$\endgroup\$
    – user107839
    Jul 12, 2016 at 4:44
  • \$\begingroup\$ Excellent answer. Upvote. \$\endgroup\$
    – SDsolar
    May 12, 2017 at 17:53

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy