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This question already has an answer here:

For example,

enter image description here

The resistor above has four colors. Green, blue, red, gold.

My calculation says its value is 562 ohms +-10%. But this page says its value is 5.6K-1/4W. What is my mistake?

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marked as duplicate by Blup1980, Bence Kaulics, Vladimir Cravero, Sparky256, Community Jul 14 '16 at 18:41

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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    \$\begingroup\$ the 2 stands for the number of zeroes, so "56 0 0" aka 5600 aka 5k6/5.6k \$\endgroup\$ – Wesley Lee Jul 14 '16 at 16:14
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    \$\begingroup\$ With your system, how would you indicate any resistance over 999 ohms? \$\endgroup\$ – brhans Jul 14 '16 at 16:25
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The third band (adjacent to the tolerance band) is a multiplier. This means that it is the number of zeroes after the first two digits. For example, a brown-red-orange-gold resistor would be 1 2 000 (three zeroes, since orange stands for 3) ohms.

For the record, a gold band means 5%, not 10%.

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It is 5.6K 5%. The first two bands give you the value (56), the third is the multiplier (10^2) so 100 * 56 = 5600\$\Omega\$, and the final band is the tolerance (gold = +/-5%).

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Well, in this 4 band resistor, the 4th band is actually % rating, as you guessed. However depending on how you google for tables, you have to search for "3 band resistor table" (yes, its confusing.. maybe the 4th band was an addendum/optional?).

So the first two bands represent algarisms, and the third represents an "n" multiplier (10ˆn).

So the value is given by:

[("band 1" *10) + (band 2)] * 10ˆ(band 3).

[50 + 6] * 100 = 5600, aka 5.6k, aka 5k6.

Or more roughly put:

Band 1 = algarism 1

Band 2 = algarism 2

Band 3 = amount of zeroes

In a resistor with 5 color bands (the 5th being %), the same applies, but the first 3 bands are algarisms and the 4th is the multiplier.

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