I've inherited an charge amplifier/shaping circuit from my predecessor. When he wanted to make a low-pass filter with current-to-voltage conversion, he had a standard circuit like:


simulate this circuit – Schematic created using CircuitLab

He would make a single footprint for R9 and C11 and solder them on top of each other like this:

PCB with Stacked Feedback Components

What reasons could he have had for designing the circuit this way? I have not seen this particular technique anywhere else. To my eye, it looks problematic, both from an assembly point of view as well as for minimizing the capacitor's feedback path. For what it is worth, the circuit is meant to deal with extremely short (~4ns) pulses.

Edit: Thanks for the insightful comments! The idea behind this circuit is, indeed to widen the pulses generated by, in this case, a PIN Diode. The capacitor is COG +/-10%.

To expand on my confusion regarding this circuit, I agree that parasitics are changed by stacking. But I should have mentioned that the capacitor and resistor are both 0603 (if it wasn't clear from the picture). I'd have thought that if the designer were concerned about parasitics, his first step would have been to reduce the component size.

I'm correcting some other issues with the board and wanted to make sure I wasn't missing something critical in this stacking business. Thanks again for the useful insight.

  • 1
    \$\begingroup\$ That's certainly a way to deal with stray inductance... \$\endgroup\$ – Ignacio Vazquez-Abrams Jul 26 '16 at 16:42
  • 5
    \$\begingroup\$ The circuit has a 40 kHz corner frequency. I don't think stray inductance is an issue here. However, given the 4 pF designed capacitance, minimizing stray capacitance might be what's intended. I'd also look carefully at layout features like ground cut-outs below these parts and the wires connecting to them. \$\endgroup\$ – The Photon Jul 26 '16 at 16:55
  • 5
    \$\begingroup\$ @EugeneSh., except for the fact the silkscreen has both designators. \$\endgroup\$ – The Photon Jul 26 '16 at 16:59
  • 2
    \$\begingroup\$ The first problem is that the OPA846 isn't stable at gains below 7 so without detail of the "so-called" current source this question looks dead to me. More likely the engineer has "learnt" this trick from a design that used it for a different reason. \$\endgroup\$ – Andy aka Jul 26 '16 at 17:00
  • 2
    \$\begingroup\$ @Seth - that photodiode has 3000 pF self capacitance and this means that the engineer who designed the circuit has no idea what he is doing - that 4 pF value will be wrong and the circuit will suffer from really bad noise values. The 4 pF should be a lot higher and the need to have it on-top of the resistor is now negated. If the photodiode were maybe ~40 pF then yes there might be a reason but not when it is 3000 pF!!! \$\endgroup\$ – Andy aka Jul 27 '16 at 7:14

Forget the 40kHz- this kind circuit really likes to oscillate at very high frequency- the feedback resistor is almost open (1M) at high frequencies in comparison to a few pF and the amplifier has a gain-bandwidth product of 1.75GHz. It's similar to a photodiode transimpedance amplifier in that respect. More importantly, you are measuring inputs with very high frequency content.

Seems to me that he wants to minimize as well as control the value of the stray capacitance on the inverting input and across the 4pF cap. At high frequencies (as implied by the 4ns pulses and the amplifier roll-off) this is basically a capacitive circuit- output voltage is input current integrated over time divided by ~4pF. The 4pF feedback (integrating) capacitor (and the amplifier input capacitance) are not greatly larger than stray capacitance from traces and pads. Even the resistor itself adds maybe 1% to the capacitance (assuming 0603).

Of course this kind of thing sometimes shows up as a 'field enhancement' (for example an amplifier oscillates so a cap is stuck on top of the feedback resistors) but it was clearly intentional in this case.

| improve this answer | |
  • \$\begingroup\$ You are correct in assuming that this circuit acts as a transimpedance amplifier and that the components are 0603. My current thought is that this is superfluous as the capacitor is +/-10% and we add only 1% due to 0603 leads. I imagine that we could reduce that further by substituting 0402 (or even 0201, given the low power dissipation) or would you imagine a remaining benefit? \$\endgroup\$ – Seth Jul 26 '16 at 23:26
  • \$\begingroup\$ The traces and pads would likely have a lot more capacitance than the tiny end-to-end capacitance of a 0603, but I suspect the benefits are in fact marginal. \$\endgroup\$ – Spehro Pefhany Jul 27 '16 at 0:51

As @IgnacioVazquez-Abrams said, this is a common method for reducing stray inductance which could lead to unwanted oscillations. I have actually seen this method used quite often, especially in circuits more sensitive to excess inductance and oscillations. Simply put, it improves the performance of the filter.

In slower circuits where stray inductance may not be as much of a problem, this method could still be used for saving space on the PCB in high-density designs.

It's certainly not ideal for production as I doubt pick & place machines are really designed to do this. I imagine this would have to be done by hand, which would increase the time requirements and cost.

While it is not the case in your particular example, this method can also be used to trim resistance/capacitance values. If the resistance is a bit too high, one might put another resistor on top of it to reduce the equivalent resistance. Similarly, putting a capacitor on top of another capacitor will increase the capacitance.

| improve this answer | |
  • \$\begingroup\$ Does this construction make sense in a filter with a 40 kHz corner frequency? \$\endgroup\$ – The Photon Jul 26 '16 at 16:52
  • \$\begingroup\$ Hmm, perhaps it was just for space-saving. I've edited my answer. \$\endgroup\$ – DerStrom8 Jul 26 '16 at 17:00
  • \$\begingroup\$ It's because for some reason they use 4pF, and they need it to be quite accurate. Otherwise the bandwidth will vary mich \$\endgroup\$ – Gregory Kornblum Jul 26 '16 at 17:23
  • \$\begingroup\$ I have seen smd capacitors double stacked in RF circuits as standard procedure. The labor to manually add one on top of another is small. I held them in place with a toothpick. Tack solder one end, then the other, then add solder both sides for a strong connection. The solder in the photo looks very shiny like tin/lead solder does. \$\endgroup\$ – user105652 Jul 26 '16 at 17:57
  • 1
    \$\begingroup\$ @Sparky256 I'm not saying it's hard to do by hand, I'm just saying that the fact that it has to be done by hand increases the required time and cost for the assembly process. \$\endgroup\$ – DerStrom8 Jul 26 '16 at 17:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.