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I am trying to design a basic project to multiplex a 3x3 LED grid in a common anode arrangement. In order to avoid sinking (sourcing?) too much current from the digital I/O pins of the Arduino I would like to uses NPN transistors as a low-side switch for each column.

I understand the case where I use a transistor to switch a single LED with the anode connected to Vs. However, I am having difficulty in designing the circuit for the multiplexed approach.

As my circuit stands I can't understand how to to wire it to source current from Vs and using I/O to control the flow.

Any pointers would be much appreciated.

enter image description here

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To source from Vs or the positive supply (I'm assuming 5V), you could connect it to the GPIO, where a logic High would be the V+ of the microcontroller, or you could connect it to PNP transistors. The PNP base would then be connected to GPIO instead, like the npn transistors are.

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  • \$\begingroup\$ I'm not sure if I understand your answer fully. If I connected 5V to the I/O rows will this not always set them high and thus I wont be able to address and control the LED rows? Thanks \$\endgroup\$ Aug 1, 2016 at 21:20
  • \$\begingroup\$ @catslovejazz, exactly, which is why you either connect the "row" to a GPIO directly, or through a PNP type transistor, both of which you can control, like you do the NPN on the low side. \$\endgroup\$
    – Passerby
    Aug 1, 2016 at 21:38
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    \$\begingroup\$ So I would have a set of NPN to control the columns and a set of PNP to control the rows? This way I will only sink/source a small amount of current from the IO pins and the LEDs will be driven by the Vs/transistors \$\endgroup\$ Aug 1, 2016 at 21:41
  • \$\begingroup\$ Yes. See cdn.instructables.com/FNB/1C5O/ICN7G649/… that said, if you are scanning them at one led at a time, you don't need either row or column transistors. A 3x3 matrix at 20mA would be easy to do directly. \$\endgroup\$
    – Passerby
    Aug 1, 2016 at 21:41
  • \$\begingroup\$ Fantastic, the only modification I would need is a resistor to limit the current in each column. \$\endgroup\$ Aug 1, 2016 at 21:43

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