# nodal analysis - CCCS controlled by current from same node

From schematics we have:

$i_1=\frac{v_1-v_2}{3},i_2=\frac{v_1-v_3}{2},i_3=\frac{v_3}{6},i_x=\frac{v_2}{4}$

for node 1:

$10 = i_1 + i_2$

$5v_1-2v_2-3v_3=60$ EQ1

for node 2:

$4i_x + i_1 - i_x = 0$

$4v_1+5v_2=0$ EQ2

for node 3:

$i_2 - i_3 - 4i_x = 0$

$6v_1 - 3v_2 -8v_3 = 0$ EQ3

from three equations we get

$v = (\frac{400}{23},\frac{-320}{23},\frac{420}{23})$

but correct solution is

$v = (80, -64, 156)$

Where is problem? My guess is that controlling current $i_x$ and dependent source are connected to same node.

The algebra for equation 3 is the problem. It should reduce to: $$3V_1-6V_2-4 V_3=0$$ That will give you the right answer
• Agreed. I found this error as well. I got $-12 v_2$ instead of $-3 v_2$ but yes, you can reduce that row. I think Matej forgot it was $4i_x$ and not $i_x$ – KingDuken Aug 4 '16 at 15:08