I initially posted this on chemistry.stackexchange but didn't get any answers, so I'm reposting it here.

Long story short - we have an electronic product that is submerged in fuels (kerosene being one of them) and uses an RGB LED (click here for datasheet). Due to a sealing problem in the enclosure, kerosene has managed to get in and cover the PCBs. What's interesting is the effect that has had on the PCB. The PCB's functionality has been completely unaffected, apart from the fact that the red LED in the RGB LED module has completely stopped illuminating. We've replicated this ourselves manually by submerging 2 new PCBs in kerosene for a day and then taking them out and powering them up and seeing that the red LED stops illuminating entirely. The green and blue LEDs continue to illuminate just fine.

Examination of the failed boards shows that there are no other electrical faults. It is just the red LED that completely stops illuminating. We measured the forward voltage across each of the LEDs in the failure condition, but didn't notice any significant difference that would explain the fault.

After leaving the PCBs to dry, the red LED starts working again. So the problem is not permanent.

Looking at the last page on the datasheet, the LED material is listed as AlGaInP / GaAs. Is there any obvious reaction between kerosene and these materials that would explain why just the red LED stops working?

Update 1: I've carried out the following experiments:

  • Dripping kerosene on to the LED.
  • Submerging the PCB+LED in kerosene while running.

(Videos to follow up later on today, hopefully)

In both cases, there was no perceived effect on the LED - it continued to operate just fine. This would seem to indicate that the problem is not purely an optical problem between the kerosene and the LED. So far, the problem has only occurred after soaking the LED in kerosene for some time.

Update 2: I've taken a fresh PCB with LED on it (haven't done any tests yet with just the LED) and soaked it in kerosene. I've taken some close up photographs of the LED before soaking, after soaking while it's not working and after it resumes working after it's been left to dry.

What the photos show is that there is a very obvious bulge in the LED lens during the period when it's not working. Once the bulge recedes, the LED illuminates again.

Unfortunately, I don't have a camera set up on the PCB to see the exact moment that it stops working. I'd let it soak for about an hour before it stopped working. I checked on the LED every now and then and noticed no change in the LED brightness. I came to check it once and it was just off. My suspicion is that the change is sudden.

Judging by the swelling, I'm going to guess that there is some mechanical damage internally that's moving something and once the swelling recedes it springs back to position.

Left: Kerosene-soaked LED; Right: Normal LED Left: Kerosene-soaked LED in failed state; Right: Normal LED

LED in failed state after soaking LED in failed state after soaking

Normal LED Normal LED

Left: Kerosene-soaked LED after being left to dry and in the working condition; Right: Normal LED Left: Kerosene-soaked LED after being left to dry and in the working condition; Right: Normal LED

Kerosene-soaked LED after being left to dry and in the working condition Kerosene-soaked LED after being left to dry and in the working condition

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    \$\begingroup\$ What does "doesn't work" mean? Does it only mean you can't see any light, does it mean the diode gets a very high or a very low DC resistance? I.e. does the forward voltage change, or the current at a fixed voltage? \$\endgroup\$ Aug 16, 2016 at 9:44
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    \$\begingroup\$ Wild guessing: maybe the kerosene is optically opaque to red light (especially the wawelength of your red LED models). Try to see if a red LED light can be seen through a glass full of kerosene, but keeping the LED outside the glass. \$\endgroup\$ Aug 16, 2016 at 9:57
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    \$\begingroup\$ Does this happen with a red LED in a minimal circuit on long leads, just immersing the LED? Does it stop working immediately or after a period of time? \$\endgroup\$
    – pjc50
    Aug 16, 2016 at 10:05
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    \$\begingroup\$ To those possibly thinking this is off-topic and it belongs to Physics.SE, IMO it is not. Although I concede physicists could know better about the phenomenon at hand, it is completely on topic here, since it is about the materials with which an actual part is made of and its interaction with the external environment. I think it is a very good question for this site (EE design applied to harsh/extreme environment). IMO this is one of those edge cases where cross-posting is useful/needed. \$\endgroup\$ Aug 16, 2016 at 12:22
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    \$\begingroup\$ Just to make sure... You're not using red-dyed Kerosene, right? Because that's a very common thing: agriculture.ny.gov/WM/Kerosene.html \$\endgroup\$
    – JPhi1618
    Aug 16, 2016 at 14:27

3 Answers 3


We measured the forward voltage and didn't notice any change.

Physically, I'm pretty sure this means the semiconductor interface is still producing photons at the same rate and wavelength as before.

So, something happens to those photons.

What you should do is get a working source of red light of the same wavelength (e.g. another one of your LEDs), extract the "lens" material from a "donor" LED:

LED picture

e.g. by cutting it off with a razor blade, testing transmission of red light before and after having soaked that material in kerosene.

Since that lens is tiny, you should probably use something like a piece of cardboard with a hole punched through it with some kind of needle (don't let the hole get to small, lest you want to have much diffraction...) and put the lens in front of that hole.

My guess is that soaking the material in kerosene leads to a drastic change in optic properties, and that might very well mean that either

  1. your lens is now absorbing red light or
  2. your lens is now not focussing red light, but spreading it.

To rule out 2., you'd need a very very dark room and some way to guesstimeasure the distribution of light. So in effect, without optical design lab equipment, either way, Kerosene contains a mixture of different hydrocarbons, and those are soluble in other hydrocarbons, such as the transparent material used to protect the actual LEDs and act as a lens.

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    \$\begingroup\$ well, most plastics aren't used for LED lenses! \$\endgroup\$ Aug 16, 2016 at 13:03
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    \$\begingroup\$ FYI, plastics used for optical devices are amorphous, since crystalline plastics are typically opaque. \$\endgroup\$ Aug 16, 2016 at 13:50
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    \$\begingroup\$ @DmitryGrigoryev that's exactly what confuses me here, and why I'd love to see OP do these experiments. We both agree that if forward voltage doesn't drop, the same photons should be emitted, and the LED as is operating "normally", so this pretty much has to be an optical effect. \$\endgroup\$ Aug 16, 2016 at 14:01
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    \$\begingroup\$ I've tried dripping kerosene on to the LED and submerging it, but there is no immediate effect on the LED. I'll try soaking it while it's running and see if there are any gradual changes. \$\endgroup\$
    – Amr Bekhit
    Aug 17, 2016 at 8:49
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    \$\begingroup\$ @AmrBekhit make sure that you're submerging just the led (i.e. desolder it from the board and hang it off of some wires), to simultaneously make sure that it's actually the LED itself acting up and not some obscure effect in some other part of the board. \$\endgroup\$ Aug 17, 2016 at 9:14

My 5 cents:

Most LEDs are potted with silicone today. Silicone has a good permeability for VOCs (volatile organic compounds, e.g. alkanes and their isomeres), which are part of kerosene.

VOCs entering the silicone can interact with the silicone matrix, changing its optical properties. Often observed damage: the potting/lens can get milky or diffuse, and yellowing can be observed.

Certain VOCs will be broken up by the blue light of an LED which usually leads to a blackening of LED potting/lenses.

Those effects are known to be (partially) reversible. I.e. the discoloration of the lenses will disappear if the VOCs are able to gas out again. This happens faster if heated under the LED's operating conditions.

So my explanation is: Edit:Highly speculative Large amounts of kerosene may contain also aromatic compounds, which are known to be optically active (e.g. See azo dyes pigments). Van der Waals forces can change the resonant behaviour of aromatic compounds, which is possible when the VOCs enter a silicone rubber matrix. This could explain why fractions of the kerosene achieve a red filtering behaviour when entering the potting.

Edit: I cannot rule out interaction of VOC with the semiconductor itself, but I habe difficulties imagining how this could work. The crystal is nearly impermeable for anything at room temperature hence the interaction can only happen at the surface of the dice. Because light emission happens everywhere near the pn-boundary I doubt that kerosene components can prevent the generation of photons. IMO only absorption and filtering are the effects to look after again.

Another culprit in LED deterioration is hydrogen sulfide, which can be found among other sulfur compounds in kerosene, too. But sulphur corrosion in LED isn't reversible AFAIK, so this can be excluded IMO.

  • \$\begingroup\$ Could these changes also include start of fluorescense? Absorb visible light reemitting it somewhere in the IR? Would you -if so- be able to see these photons with a webcam? \$\endgroup\$
    – peter
    Aug 16, 2016 at 21:04
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    \$\begingroup\$ There are several excellent resources describing the issue with VOC absorption in LEDs from some manufacturers eg. Cree, OSRAM. I am not sure if this would be the issue with the OP's LEDs though - they are relatively low power and I guess the absorbed VOC are less likely to decay in the way they do with bright/hot high power LEDs. \$\endgroup\$
    – Matt B
    Aug 17, 2016 at 3:50
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    \$\begingroup\$ The recovery effect as the VOC evaporates out of the silicone packaging definitely does occur - I've observed it myself in LEDs that had absorbed VOC produced by glue used elsewhere in the device. \$\endgroup\$
    – Matt B
    Aug 17, 2016 at 3:50
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    \$\begingroup\$ Thanks for your answer. After examining one of the LEDs when it was in its failure state, I couldn't notice anything visibly wrong with it. There was no sign of any clouding or occlusion - the lens seemed perfectly clear. I'm going to try and repeat the test and get some photographs so that I can post them up. \$\endgroup\$
    – Amr Bekhit
    Aug 17, 2016 at 12:27
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    \$\begingroup\$ Follow up on this, I had a look at the LEDs on two PCBs that I had tested a week or so back and there is very noticeable yellowing of the LED lens. So this reaction with the kerosene you mention seems to be happening. However, I've just updated the question with some photographs showing bulging of the LED lens in the failed state after being soaked. I have a feeling that the problem is mechanical in nature, i.e. the bulging is disconnecting something. \$\endgroup\$
    – Amr Bekhit
    Aug 19, 2016 at 13:44

My guess is that the kerosene absorbs the red photons and heats up the plastic lense causing it to bulge, which in turn causes dispersion of the photons. So you have the double effect of absorption and dispersion of the red photons. There is also the possibility that at some point, the heat produced swelling of the plastic, creates a high resistance connection, which goes back to "normal" after the LED dries.

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    \$\begingroup\$ Although I didn't mention this detail in the original question, I know that this is not the case. This is because if you leave the PCB in the kerosene unpowered and then take it out and power it up, it won't work. Therefore, the bulging has got nothing to do with the light being produced and is purely due to exposure to the kerosene. \$\endgroup\$
    – Amr Bekhit
    Aug 22, 2016 at 7:49

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