V = IR = 2A * 5ohms = 10V
Total power = VI = 6*2 = 12W
Power absorbed in R1 would then be I^2 * R = 50W
Now why does the voltage drop not equal the source voltage according to KVL? The only reason that I try to calculate it in the first place is because I assume that, due to the question, that there will be a voltage drop across the current source.
Also, why is my power calculation way off? Obviously the power dissipated in one element won't be greater than the power supplied. Help with the power delivered/absorbed in the other two elements would also be great.
Any help would be really appreciated. This is a practice exam paper not homework.