10
\$\begingroup\$

I'm trying to learn PCB design and, from what I've read and seen, there appear to be three different types of vias:

  1. Through hole - goes all the way through the board
  2. Blind - goes from the top or bottom layer to some layer in between the top and bottom, but not all the way through
  3. Buried - is between the top and bottom layers

It seems like most semi-complex boards I've had the opportunity to look at are 4-layer boards, and that usually one layer is dedicated to GND, another to VCC, and then the other two have traces. My question is what kind of via is most appropriate when trying to connect a pad or trace from one layer to the GND or VCC layers? I ask because I would have thought that a blind or buried via should be used, but it seems like most boards I've looked at use through hole vias and that there's just a stop around the via on the layers it's not supposed to be connected to. Is there a reason to use that method instead of using a blind or buried via?

\$\endgroup\$
2
  • 5
    \$\begingroup\$ Use regular vias that go all the way thru the board stack unless you have a good reason not to and understand the tradeoffs. Put another way, if you have to ask, stick to thru hole vias. \$\endgroup\$ Commented Jan 21, 2012 at 20:21
  • \$\begingroup\$ This question is very similar to electronics.stackexchange.com/q/240725/104097. \$\endgroup\$
    – sa_leinad
    Commented Feb 23, 2018 at 8:00

2 Answers 2

17
\$\begingroup\$

Blind and buried vias add a lot to the cost of a multi-layer board, and are only used on high-density, high-performance systems. The increase in cost is because the layers have to be drilled separately, assembled, and then the holes are plated. Blind vias are sometimes back-drilled (the unwanted plating is removed with a slightly larger drill from the back) which reduces the cost, as the layers are stacked before drilling.

\$\endgroup\$
4
  • 5
    \$\begingroup\$ Just to add a bit to Leon's answer: Very little (none?) consumer electronics use blind/buried vias. They can't handle the cost increase and the benefits for those devices don't justify the cost. This includes PC motherboards that are super dense and super fast. I mention this because odds are that whatever you are designing doesn't require blind/buried vias. \$\endgroup\$
    – user3624
    Commented Jan 21, 2012 at 17:42
  • \$\begingroup\$ Most likely, if you need blind/buried then you need a pro to do the layout for you. Make sure the PCB fab house is well experienced if you do need them; they are very difficult to get done right, especially when matching impedance for high-speed traces. \$\endgroup\$ Commented Jan 22, 2012 at 0:50
  • \$\begingroup\$ It's a tradeoff, blind/buried vias cost extra money but so do extra layers. I haven't done such designs myself but my understanding was that a 6 layer with blind vias was more economical than 8 layer without blind vias. \$\endgroup\$ Commented Apr 28, 2017 at 18:55
  • 4
    \$\begingroup\$ 2017 update, for those arriving from Google: blind & buried vias are now common in consumer electronics, particularly items such as smartphones and wearables. \$\endgroup\$ Commented Jun 21, 2017 at 21:13
12
\$\begingroup\$

Cost..

Here is a small example, I hired an inexperienced guy, he made a 4 layer PCB design, 30x50mm board. I sent to get a quote, I get a quote for 2K USD for 20 pieces, I naturally objected. They have said, this has buried vias. Later, I changed the design sent the gerbers back, price was 150$ in 5 working days.

Unless you have BGA package, don't use any via other than through hole.

\$\endgroup\$
1
  • 2
    \$\begingroup\$ Even for BGA's, you don't need to even consider them unless the ball pitch is 0.65mm or less. Many 0.65 and 0.50 mm pitch BGAs can still be done without them. \$\endgroup\$
    – user3624
    Commented Jan 22, 2012 at 6:05

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.