I want to supply a DSP with 1.2V. This DSP needs 2.6 Amps of current at full load. The minimum supply based on the electrical specs of this DSP is 1.16V, which means that the maximum voltage drop caused by power planes, traces and connectors should not exceed 40 mV.
In my case, I found it very hard to achieve this since the distance between power source and DSP is about 8000 Mil (~ 20 cm) and this supply passes by two connectors which add 100 mOhms, so the drop is 260 mV (100m x 2.6A) without counting in planes impedance. I drew a simple schematic for my case shown in the next image:
My questions are:
Is the total distance only 20 cm? or should I add the return so that the actual distance is 40 cm ? ( Much worse :( )
How can I solve this issue? knowing that the distance between source and DSP can't be less than 20 cm. Should I add another regulator beside the DSP? or is it better to generate a slightly larger voltage to compensate this drop? (there is other components the need 1.2V supply and are at different distances from the DSP).
How can I calculate the plane impedance, shown in the above image as R(Plane)?
# Edit 1:
Regarding point 1, ok, the total distance now is unfortunately 40 cm.
I thought of a solution to reduce the connectors resistance, which are the main factor of high resistance. According to connectors data sheet, the resistance of the pin is 25 mOhms, I have extra free pins, so I'll use 8 Pins to transmit the 1.2V so that the is now divided by 8, but the question now is, I don't know if this resistance is for the pin only or is it the total after mating? and after mating should they be treated as series or parallel resistors?