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I have an optical encoder with four wires: Green = A phase, white = B phase, red = Vcc positive power supply, black = V0.

Additionally, it has a metal shielding layer in the cable. Now I don't know what is the use of this metal shielding. Can anybody provide some information about it?

product image of rotary encoder

image of pigtail cable of the encoder

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  • \$\begingroup\$ Connect it to the ground/earth. \$\endgroup\$ – Marko Buršič Sep 5 '16 at 12:55
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It's the shield. Usually you should connect it to the ground (instrumentation side).

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  • \$\begingroup\$ What if i leave it as it is? \$\endgroup\$ – TIWARI Sep 5 '16 at 10:58
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    \$\begingroup\$ Not a good idea.. if you want to go in deep, the web is full of resource, like this or this. \$\endgroup\$ – Antonio Sep 5 '16 at 12:07
  • \$\begingroup\$ Why downvoted? How I should improve this answer? \$\endgroup\$ – Antonio Sep 5 '16 at 13:44
  • \$\begingroup\$ I guess the downvoter would have liked if you explain why should the shielding connected. But it is just a guess. \$\endgroup\$ – Bence Kaulics Sep 5 '16 at 15:16
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    \$\begingroup\$ @TIWARI Some devices have ground as a reference (stable) potential. Disconnecting it you are making it floating (instable) reference. Other devices use ground for security. Disconnecting it you are making this security knowingly inefficient. Ground shall be the first to be connected and last to be disconnected. Keep it as eleventh commandment :) \$\endgroup\$ – Crowley Sep 5 '16 at 15:58

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