In the LM386 datasheet it's stated that "If a capacitor is put from pin 1 to 8, bypassing the 1.35 kΩ resistor, the gain will go up to 200 (46 dB)".
I don't understand how this capacitor could bypass the resistor. I've tried simulating this scenario in EveryCircuit and current keep flowing in the resistor and it makes sense to me since DC won't flow into the capacitor.
They make it sound like by adding this capacitor the resistor will be shorted but I don't see how this could happen.
What are we trying to achieve in term of current/voltage flow here by adding this cap?